#include<bits/stdc++.h>

using namespace std;
//鸡兔同笼的一维求解方法
int main() {
    int n = 10, m = 28;

    int x, y;
    int flag = 0;
    for (x = 0; x <= 10; x++) {
        y = n - x;
        if (2 * x + 4 * y == m) {
            printf("(%d,%d)\n", x, y);
            flag = 1;
            break;
        }
    }
    if (flag == 0) {
        puts("No answer");
    }
    return 0;
}
